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6r^2-32=-44r
We move all terms to the left:
6r^2-32-(-44r)=0
We get rid of parentheses
6r^2+44r-32=0
a = 6; b = 44; c = -32;
Δ = b2-4ac
Δ = 442-4·6·(-32)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2704}=52$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-52}{2*6}=\frac{-96}{12} =-8 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+52}{2*6}=\frac{8}{12} =2/3 $
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